Forms in PHP

[admin]

Could somebody please give me some assistance.

I have written a PHP script for MySQL which can be viewed at
http://a-i-s.net/temp/mission2.php
If you look at the source code you will see the variable $Guest is hard coded.

How do I use a form to input the value of $Guest from a drop down list.

Thanks.

[admin]

Hope that helps

<select size="1" name="D1">

<?while ($row= mysql_fetch_row($result))


Echo "<option >".$row=["col"]."</option>"

?>


</select>

regards
F2p

[admin]

<select size="1" name="D1">

<?while ($row= mysql_fetch_row($result))

{
Echo "<option >".$row=["col"]."</option>"
}
?>


</select>

forgot the {}

[admin]

Re ; PHP Forms

Hi,

Thanks for the response.

Ok know how to setup up a form and the drop down list.

What I actually need is how do I make the form option value work with the script.

i.e. The value in the form must become part of the SELECT statement in the query e.g. LIKE '$option'

[admin]

If you want a variable $Guest be set in the action script of the form, simply name an input Guest:
<input type=text name=Guest>

You can even do this with linear arrays (vectors):
<input type=checkbox name="check[]" value=1>check 1
<input type=checkbox name="check" value=2>check 2
for ($i=0;$i<count($check);$i++) echo $i.'<br>';
(or: echo implode('<br>',$check);
will output the values of all checked boxes, if any was checked. if not, $check will be unset (and so may not be used as an array)

-=* Titus *=-
| php pro |
|nerd for life|
"""""""""""""""

[admin]

or for a dropdown:
<select name=dropdown>
<option value="1">first</option>
<option value="2">second</option>
<option value="3">third</option>
</select>

multiple choice:
<select multiple size=3 name="multiple[]">
<!-- remember the array part? -->
<option value="1">first</option>
<option value="2">second</option>
<option value="3">third</option>
</select>

[admin]

Solved

Thanks for the hints.

My problem was I was using the variable form $Guest instead of the plain form Guest for the name.